How to Convert a String to an Integer in JavaScript

Converting a string to an integer is a common task in JavaScript. Whether you’re processing user input or working with data from APIs, JavaScript provides several easy-to-use methods for this conversion. This guide covers three reliable ways to convert strings to integers.

1. Using parseInt()

The parseInt() function parses a string and returns an integer. It also allows specifying the number system (radix) for conversion.

const str = ""42"";
const number = parseInt(str, 10);
console.log(number); // Output: 42

Key Details

• The second argument, 10, specifies the radix (base 10). Always include it to avoid unexpected behavior with non-decimal numbers.
• If the string starts with non-numeric characters, parseInt() ignores them until it encounters numbers:

   parseInt(""42abc"", 10); // Output: 42
   parseInt(""abc42"", 10); // Output: NaN

2. Using Number()

The Number() function converts the entire string into a number. Unlike parseInt(), it does not ignore non-numeric characters and fails if the string contains invalid data.

const str = ""42"";
const number = Number(str);
console.log(number); // Output: 42

Key Details

• Returns NaN if the string contains invalid characters:

   Number(""42abc""); // Output: NaN

• Works best when the string is strictly numeric.

3. Using the Unary + Operator

The unary + operator is a shorthand way to convert a string into a number. It’s concise and works like the Number() function.

const str = ""42"";
const number = +str;
console.log(number); // Output: 42

Key Details

• Like Number(), it converts the entire string and returns NaN for invalid input:

   +""42abc""; // Output: NaN

Handling Invalid Input

To avoid unexpected results, always check if the conversion is valid using isNaN():

const str = ""42abc"";
const number = parseInt(str, 10);

if (isNaN(number)) {
  console.log(""Invalid number"");
} else {
  console.log(""Valid number:"", number);
}

Conclusion

Converting a string to an integer in JavaScript is simple with parseInt(), Number(), or the unary + operator. Choose the method that fits your use case, and always handle invalid input to ensure reliable results.

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